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5p^2+36p-32=0
a = 5; b = 36; c = -32;
Δ = b2-4ac
Δ = 362-4·5·(-32)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-44}{2*5}=\frac{-80}{10} =-8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+44}{2*5}=\frac{8}{10} =4/5 $
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